I think I found the binary GPS data
SE in |ASE.>.cE.H.F=..A| suggest correct hemisphere. Although it looks a bit empty (not time data?).
Code:
082b7f00 47 50 53 20 4c 00 00 00 00 00 00 00 00 00 00 00 |GPS L...........|
082b7f10 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
082b7f20 00 00 00 00 00 00 00 00 0a 00 00 00 1b 00 00 00 |................|
082b7f30 04 00 00 00 10 00 00 00 07 00 00 00 0f 00 00 00 |................|
082b7f40 41 53 45 00 3e f0 63 45 d2 48 88 46 3d 0a db 41 |ASE.>.cE.H.F=..A|
082b7f50 7b 14 36 42 00 00 00 00 00 00 00 00 00 00 00 00 |{.6B............|
082b7f60 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
082b8ef0 00 00 00 00 00 00 00 00 00 00 20 00 66 72 65 65 |.......... .free|
Edit: 3e f0 63 45 works out to 3647.01513671875 and d2 48 88 46 to 17444.41015625
Which works out to
here, which is very accurate.
Also next 4bytes 3d 0a db 41 work out to 27.3799991607666 (knots?) and 7b 14 36 42 to 45.52000045776367 (bearing). The 27knots or so work out 50km/h which is also about right, as well as 45' bearing.