BobDiaz
Well-Known Member
I'm thinking that a small CPU cooling fan would do the trick and the best part is, I don't have to run it at full speed. I could add a resistor in series with the fan to keep the noise down.
Source: http://en.wikipedia.org/wiki/Computer_cooling
Assume that I'll only allow a 36F (20C) rise in heat, the calculation would be: 1.76 x 1.5 Watts / 20C = 0.132 CFM of air flow. That comes to 0.99 gallons of air every minute or 3.7 liters of air every minute. That's about 2 oz of air per second or 62 ml of air per second. So not a lot of air need to move across the heatsink.
... Now if only SpyTec would stock the wide angle lens version ...![Big grin :D :D](https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f600.png)
![b92b2fab814f1a64fc04c8c67b649cb7.png](/forum/proxy.php?image=http%3A%2F%2Fupload.wikimedia.org%2Fmath%2Fb%2F9%2F2%2Fb92b2fab814f1a64fc04c8c67b649cb7.png&hash=273001188553b884d2ccbf577fb71ee1)
![833a13f5116fcaf4bcc53320d016c32a.png](/forum/proxy.php?image=http%3A%2F%2Fupload.wikimedia.org%2Fmath%2F8%2F3%2F3%2F833a13f5116fcaf4bcc53320d016c32a.png&hash=f90d3ab14fedcc3f11e65277cb18b2f2)
Source: http://en.wikipedia.org/wiki/Computer_cooling
Assume that I'll only allow a 36F (20C) rise in heat, the calculation would be: 1.76 x 1.5 Watts / 20C = 0.132 CFM of air flow. That comes to 0.99 gallons of air every minute or 3.7 liters of air every minute. That's about 2 oz of air per second or 62 ml of air per second. So not a lot of air need to move across the heatsink.
... Now if only SpyTec would stock the wide angle lens version ...
![Big grin :D :D](https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f600.png)