ChampaRando
Member
*Sorry removed my earlier post. I was too impatient lol. Should have completed my maths properly.*
Reposting.
Another question for you guys. I've just found out (no I did not know this before - not an electrical engineer or anything haha). So most powerbank's capacity is at 3.7V (because of the way of lithium cells yeah).
So for a 5V output, there is naturally loss and the rough estimate is around 5V = 3.7V*mAh/5V. So if we consider a 10,000mAh Power bank, charging a phone, it's more around (not exactly) 7400mAh+heat loss/etc for 5V draw.
Also I assume, if we pull 9V (for example fast charging) OR 12V for a camera hard-wire into power bank for example, that would mean I have further mAh loss? Correct?
So looking at the Cellink/Blackvue Battery packs or others, they mention this;
So that 6,000mAh they say, I am sure they mean it at 12.8V itself thus the 76.8Wh rating (6000mAh/1000=6Ah*12.8V = 76.8Wh).
So if I was to use a 3.7V 40,000mAh powerbank and pull out 12.8V from it, that means I end up with a capacity of 11,562mAh@12.8V (11,562mAh = 3.7V*40,000mAh/12.8V) + normal heat/conversion loss whatever. Assuming lossless conversion, that still equates to 11.5625Ah*12.8V=148Wh.
So even though that Cellink/Blackvue battery is 6000mAh@12.8V, and this powerbank is 40,000mAh @ 3.7V, this powerbank is only roughly 2X larger correct and will power the camera at 12V for roughly 2X longer? (76.8Wh vs 148Wh). Is my math and understanding correct?
Also: How much wattage (also voltage and amps) do dashcams normally use in 2CH? I know it differs but roughly. Is it actually 5V or do dashcams actually operate at 12V? Do hardwires step down voltage (thus some power loss). What exactly does a hard-wire kit do? What's that little box in Viofo kits fot example with voltage settings actually doing? Is it downstepping 12V to 5V. Correct? Thus some power loss?
Cheersio!
Reposting.
Another question for you guys. I've just found out (no I did not know this before - not an electrical engineer or anything haha). So most powerbank's capacity is at 3.7V (because of the way of lithium cells yeah).
So for a 5V output, there is naturally loss and the rough estimate is around 5V = 3.7V*mAh/5V. So if we consider a 10,000mAh Power bank, charging a phone, it's more around (not exactly) 7400mAh+heat loss/etc for 5V draw.
Also I assume, if we pull 9V (for example fast charging) OR 12V for a camera hard-wire into power bank for example, that would mean I have further mAh loss? Correct?
So looking at the Cellink/Blackvue Battery packs or others, they mention this;
So that 6,000mAh they say, I am sure they mean it at 12.8V itself thus the 76.8Wh rating (6000mAh/1000=6Ah*12.8V = 76.8Wh).
So if I was to use a 3.7V 40,000mAh powerbank and pull out 12.8V from it, that means I end up with a capacity of 11,562mAh@12.8V (11,562mAh = 3.7V*40,000mAh/12.8V) + normal heat/conversion loss whatever. Assuming lossless conversion, that still equates to 11.5625Ah*12.8V=148Wh.
So even though that Cellink/Blackvue battery is 6000mAh@12.8V, and this powerbank is 40,000mAh @ 3.7V, this powerbank is only roughly 2X larger correct and will power the camera at 12V for roughly 2X longer? (76.8Wh vs 148Wh). Is my math and understanding correct?
Also: How much wattage (also voltage and amps) do dashcams normally use in 2CH? I know it differs but roughly. Is it actually 5V or do dashcams actually operate at 12V? Do hardwires step down voltage (thus some power loss). What exactly does a hard-wire kit do? What's that little box in Viofo kits fot example with voltage settings actually doing? Is it downstepping 12V to 5V. Correct? Thus some power loss?
Cheersio!
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